Parallel lines are cut by a transversal such that the alternate interior angles have measures of 3x + 17 and x + 53 degrees. The value of x is
9
18
35
71

When parallel lines are cut by a transversal, the alternate interior angles are equal.3x + 17 = x + 53Subtract 'x' from each side:2x + 17 = 53Subtract 17 from each side:2x = 36Divide each side by 2 :x = 18

Well the sum of the alternate interior angles of a transversal cutting parallel lines should be equal to 180'. So (3x+17)=(x+53)3x+17=x+53Using transposition method-3x-x=53-172x=36x=36/2x=18Hopw i helped!