Find the area of a triangle that has a base of 5 in and a height of 3 3/4 in

Remember:[tex]3\frac{3}{4}=\frac{15}{4}[/tex]Area of a triangle[tex]A=\frac{1}{2}.b.h\\
\\
A=\frac{1}{2}*5*\frac{15}{4}=\frac{75}{8}=9\frac{3}{8} \ in^2[/tex]

[tex]Area= \frac{bh}{2}
\\ \\ 5*3.75=18.75
\\ \\ \frac{18.75}{2} = 9.375
\\\\\boxed{9.375}[/tex]