Two cars leave Denver at the same time and travel in opposite directions. One car travels 10 mi/h faster than the other car. The cars are 500 mi apart in 5 h. How fast is each car traveling?

The speed of one car is 'S'.  The speed of the other car is (S + 10).In 5 hours, the first car travels (5S) miles, and the other car travels  5(S + 10) miles.Since they're going in opposite directions, the distance between them at any timeis the sum of the distance that each one has traveled.500 = (5S) + 5(S + 10)500 = 5S  +  5S + 50500 = 10S + 50Subtract 50 from each side:450 = 10SDivide each side by 10S = 45S + 10 = 55

Let one car travel at x mph
The other car travels at x+10 mph
Their combined speed is 2x+10 mph.
Distance = 500

time = 500 /2x+10 =5
10x+50=500
10x= 450
x=45 speed of one car
The other car travels at 45+10 = 55 mph