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Find three consecutive even integers whose sum is 36.

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Accepted Answer

Look at 36/3 = 12. So let's try 12 along with the one before it and the one after it.10 + 12 + 14 = 36yay !

Suggested Answer

[tex]2n+2n+2+2n+4=36\\
6n=30\\
n=5\\\\
2n=2\cdot5=10\\
2n+2=2\cdot5+2=12\\
2n+4=2\cdot5+4=14\\[/tex]

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