What is the vertical asymptote for the function f(x) = ln(x + 4) - 2? Be sure to write your answer as an equation for a line.

f(x) = ln (x+4) -2Change f(x) to yy=ln (x+4) -2Inverse x and yx=ln(y+4) -2Solve for y, result will be inverse.x+2=ln(y+4)convert to exponential form e^(x+2) = y+4y=e^(x+2) -4This is the inverse. f^-1(x) = e^(x+2) -4Looking at the above function, it is (e^x) shifted to the left by two unit, being brought down (4) units. The only important part of this function is the down-shift of (4), because this represents the horizontal asymptote. y = -4 is the horizontal asymptote, which means for f(x) =ln(x+4) -2 x=-4 is a vertical asymptotes.