if a+b+c=0 for a,b,c then prove a²/bc+b²/ca+c²/ab=3.

according to the identity if a+b+c=0then a3+b3+c3=3abca3+b3+c3/abc=3a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3cancel a,b,c in   all the fraction then you geta²/bc+b²/ca+c²/ab=3. hence proved