The dimensions of a brick that weighs 25 N are 0.19 m × 0.07 m × 0.095 m. What pressure does the brick exert on the ground if it is resting on its largest face?

Answer:The pressure of the brick exert on the ground if it is resting on its largest face is 1385.04 Pa.Explanation:Given that,Weight of brick = 25 NThe dimensions of a brick are 0.19 m × 0.07 m × 0.095 m. The pressure of the brick exert on the ground if it is resting on its largest face.So, The area of largest face of brick is [tex]A = 0.19\times 0.095[/tex][tex]A= 0.01805\ m^2[/tex]The pressure of the brick on the ground isThe pressure is the force upon area.The formula of pressure is[tex]P =\dfrac{F}{A}[/tex][tex]P=\dfrac{25}{0.01805}[/tex][tex]P = 1385.04\ Pa[/tex]Hence, The pressure of the brick exert on the ground if it is resting on its largest face is 1385.04 Pa.

p - pressure [Pa] Fn - pressure force [N]S - surface area [m²]S = 0.19m*0.095=0.01805 [m²] (the two largest values ​​of bricks)[tex]p=\frac{F_n}{S}=\frac{25N}{0.01805m^2}=1385[Pa][/tex]