What is the displacement after 6 seconds when a car is moving at 12m/s and coasts up a hill with a uniform aacceleration of -1.6 m/s^2

The kinematic formula using displacement, time, initial velocity, and acceleration:x = v t+.5 a t^2x= (12m/s)(6s) + .5(-1.6m/s^2)(6s)^2x= 72m - 28.8mx = 43.2 m